Note

[001] Multiples of 3 and 5 import time t = time.time() result = 0 for i in range(1, 100): if(i % 3 == 0 or i % 5 == 0): result += i print("RESULT : " + str(result)) print("\n[RUNTIME :: %.02f]" % (time.time() - t)) [002] Even Fibonacci numbers # 피보나치수열 홀짝되는 규칙찾으면 더빨라져 import time t = time.time() result = 2 # Because curNum starts in 3, result is initiated by 2 first, second = 1, 2 curNum = 0 whi..